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Question Number 36126 by Rasheed.Sindhi last updated on 29/May/18

x^4 +10x^3 +6x−1 =^(?) (x^2 +(((√5)−1)/2))(x^2 +10x−(((√5)+1)/2))

$$\mathrm{x}^{\mathrm{4}} +\mathrm{10x}^{\mathrm{3}} +\mathrm{6x}−\mathrm{1} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\overset{?} {=}\left({x}^{\mathrm{2}} +\frac{\sqrt{\mathrm{5}}−\mathrm{1}}{\mathrm{2}}\right)\left({x}^{\mathrm{2}} +\mathrm{10}{x}−\frac{\sqrt{\mathrm{5}}+\mathrm{1}}{\mathrm{2}}\right) \\ $$

Commented by Rasheed.Sindhi last updated on 29/May/18

Exactly sir, this is not true.

$$\mathcal{E}{xactly}\:{sir},\:{this}\:{is}\:{not}\:{true}. \\ $$

Commented by Rasheed.Sindhi last updated on 29/May/18

Dear Abu Behi In Q#35844 you factorize as above. Is this right?

$$\mathcal{D}{ear}\:\mathcal{A}{bu}\:\mathcal{B}{ehi} \\ $$$${In}\:{Q}#\mathrm{35844}\:\mathrm{you}\:\mathrm{factorize}\:{as}\:{above}. \\ $$$${Is}\:{this}\:{right}? \\ $$

Commented by MJS last updated on 29/May/18

but this is not true

$$\mathrm{but}\:\mathrm{this}\:\mathrm{is}\:\mathrm{not}\:\mathrm{true} \\ $$

Commented by behi83417@gmail.com last updated on 29/May/18

mr Rasheed! you are right.it is not true.it is just an idea.

$${mr}\:{Rasheed}!\:{you}\:{are}\:{right}.{it}\:{is}\:{not} \\ $$$${true}.{it}\:{is}\:{just}\:{an}\:{idea}. \\ $$

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