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Question Number 36328 by Rio Mike last updated on 31/May/18

$$\mathrm{find}\mathrm{the}\mathrm{perimeter}\mathrm{of}\mathrm{a}\mathrm{right}\mathrm{angle}$$$$\mathrm{triangle}4xcmhighand5xcmbase$$

Commented by Rasheed.Sindhi last updated on 02/Jun/18

$$\mathrm{Hypotenuse}=\sqrt{{\left(5\mathrm{x}\right)}^2+{\left(4\mathrm{x}\right)}^2}=\sqrt{{25\mathrm{x}}^2+{16\mathrm{x}}^2}=\sqrt{41}\mathrm{x}$$$$\mathrm{Perimeter}=5\mathrm{x}+4\mathrm{x}+\sqrt{41}\mathrm{x}=15.40\mathrm{x}$$

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