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Question Number 36366 by chakraborty ankit last updated on 01/Jun/18

	Answered by tanmay.chaudhury50@gmail.com last updated on 01/Jun/18

	$47) r e d = 3 b l u e = 4 g r e e n = 2$ $p = \frac{3 C_{1} \times 4 C_{1} \times 2 C_{1}}{9 C_{3}} = \frac{3 \times 4 \times 2}{\frac{9 \times 8 \times 7}{3 \times 2}} == \frac{3 \times 4 \times 2 \times 3 \times 2}{9 \times 8 \times 7}$ $= \frac{2}{7}$
	Answered by tanmay.chaudhury50@gmail.com last updated on 01/Jun/18

	$46) g r o u p A = 4 q u e s t i o n$ $g r o u p B = 4 q u e s t i o n$ $a t t e m t = 5 q u e s t i o n$ $o p t i o n$ $2 A + 3 B = 4 C_{2} \times 4 C_{3} = \frac{4 \times 3}{2} \times \frac{4}{} = 24$ $3 A + 2 B = 4 C_{3} \times 4 C_{2} = 24$ $t o t a l = 24 + 24 = 48$
	Answered by tanmay.chaudhury50@gmail.com last updated on 01/Jun/18

	$45) \vec{a} \times \vec{b} =∣ \vec{a} ∣∣ \vec{b} ∣ s i n θ {\vec{n}}_{1} w h e r d \vec{n} u n i t v e c t o r ⊥$ $t o t h e p l a n e c o n t a i n i n g \vec{a} a n d \vec{b}$ $g i v e n ∣ \vec{a} ∣= 1, ∣ \vec{b} ∣= 1, ∣ \vec{c} ∣= 1 a n d ∣ \vec{d} ∣= 1$ $\vec{a} . \vec{c} = 1 \times 1 \times c o s (θ) = \frac{1}{2}$ $θ = 60^{o} b e t w e e n \vec{a} a n d \vec{c}$ $c o n t d$
	Commented by chakraborty ankit last updated on 02/Jun/18

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