2 regtangle A and B given that the legnth of A is three times the legnth of B,and the Perimeter of A is 102cm. If the Area of B is same as 2 times the Area of a Trapezium with 2 parrallel sides 5cm and 4cm with hieght 6cm. find the lengths and widths of A and B.


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Question Number 36475 by Rio Mike last updated on 02/Jun/18

$2 r e g t a n g l e A a n d B g i v e n t h a t$ $t h e l e g n t h o f A i s t h r e e t i m e s t h e$ $l e g n t h o f B, a n d t h e P e r i m e t e r o f$ $A i s 102 c m . I f t h e A r e a o f B i s$ $s a m e a s 2 t i m e s t h e A r e a o f a T r a p e z i u m$ $w i t h 2 p a r r a l l e l s i d e s 5 c m a n d 4 c m$ $w i t h h i e g h t 6 c m . f i n d t h e l e n g t h s$ $a n d w i d t h s o f A a n d B .$
Commented by math1967 last updated on 02/Jun/18

$I t h i n k s o m e c o n d i t i o n i s m i s s i n g$
	Answered by tanmay.chaudhury50@gmail.com last updated on 03/Jun/18

	$r e c t a n g l e A a r e a = l_{A} \times b_{A}$ $r e c a n g l e B a r e a = l_{B} \times b_{B}$ $g i v e n l_{A} = 3 l_{B}$ $p e r i m e t e r o f A = 2 (l_{A} + b_{A}) = 102$ $l_{A} + b_{A} = 51$ $3 l_{B} + b_{A} = 51$ $l_{B} \times b_{B} = 2 \times \frac{1}{2} (5 + 4) \times 6$ $l_{B} \times b_{B} = 54$ $3 l_{B} + b_{A} = 51$ $s o t h r e e u n k n o w n (l_{B}, b_{B} a n d b_{A})$ $t w o e q u t i o n . . . s o d a t a i n s u f f i c i e t$
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