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Question Number 36576 by ast empire last updated on 03/Jun/18

Commented by prof Abdo imad last updated on 03/Jun/18

let put A = (x^(100) /(1+x+x^2 +....+x^(200) )) if x=1 A = (1/(201)) if x ≠1 A = (x^(100) /((1−x^(201) )/(1−x))) =((x^(100) (1−x))/(1−x^(201) )) ⇒ A = ((x^(100) −x^(101) )/(1−x^(201) )) .

letputA=x1001+x+x2+....+x200ifx=1A=1201ifx≠1A=x1001−x2011−x=x100(1−x)1−x201⇒A=x100−x1011−x201.

Answered by ajfour last updated on 03/Jun/18

=((x^(100) (1−x))/(1−x^(201) )) (provided ∣x∣<1 ) .

=x100(1−x)1−x201(provided∣x∣<1).

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