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Question Number 36676 by tawa tawa last updated on 04/Jun/18

$$\mathrm{if}\mathrm{z}=-27,\mathrm{find}\mathrm{all}\mathrm{the}\mathrm{root}\mathrm{of}\mathrm{z}\mathrm{in}\mathrm{complex}\mathrm{plain}$$

Commented by abdo mathsup 649 cc last updated on 04/Jun/18

$$therootsare?thecomlexz/z^2=-27={\left(i\sqrt{27}\right)}^{2}so$$$$therootsarei\sqrt{27}and-i\sqrt{27}.$$

Commented by tawa tawa last updated on 04/Jun/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

Commented by abdo.msup.com last updated on 05/Jun/18

$$alotsofthankssirTawaTawa...$$

Answered by Rasheed.Sindhi last updated on 04/Jun/18

$$\mathrm{Let}\mathrm{z}=\mathrm{x}+\mathrm{iy}$$$$\mathrm{x}+\mathrm{iy}=-27$$$$\mathrm{x}=-27,\mathrm{y}=0$$$$(-27,0)\left(\mathrm{single}\mathrm{root}\right)$$

Commented by tawa tawa last updated on 05/Jun/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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