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Question Number 37028 by nishant last updated on 08/Jun/18
∫2x−15x2−x+2dx=?
Answered by ajfour last updated on 08/Jun/18
I=15∫10x−15x2−x+2dx−425∫dx(x−110)2+25−1100=15ln∣5x2−x+2∣−425∫dx(x−110)2+(3910)2=15ln∣5x2−x+2∣−425×1039tan−1(10x−139)+c.
Commented by nishant last updated on 08/Jun/18
thankssir.
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