If ∫ ((cos 4x+1)/(cot x−tan x)) dx=A cos 4x+B, then find A,B?


Question and Answers Forum

All Questions Topic List
UNKNOWN Questions
Previous in All Question Next in All Question
Previous in UNKNOWN Next in UNKNOWN
Question Number 37189 by rahul 19 last updated on 10/Jun/18

$If \int \frac{\cos 4 x + 1}{\cot x - \tan x} d x = A \cos 4 x + B, then$ $find A, B ?$
	Answered by math1967 last updated on 10/Jun/18

	$\int \frac{2 {c o s}^{2} 2 x}{\frac{{c o s}^{2} x - {s i n}^{2} x}{s i n x c o s x}} d x$ $\int \frac{2 {c o s}^{2} 2 x s i n x c o s x}{c o s 2 x} d x$ $\frac{1}{2} \int 2 s i n 2 x c o s 2 x d x$ $\frac{1}{2} \int s i n 4 x d x = - \frac{1}{8} c o s 4 x + c$ $∴ A = - \frac{1}{8}, B = c = s o m e c o n s t a n t$ $c o r r e c t ?$
	Commented by MJS last updated on 10/Jun/18

	$correct!$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum