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Question Number 37462 by bholachaudhary211@gamil.com last updated on 13/Jun/18

$$\mathrm{If}x+3\mathrm{is}\mathrm{the}\mathrm{common}\mathrm{factor}\mathrm{of}\mathrm{the}$$$$\mathrm{expressions}{ax}^2+bx+1\mathrm{and}$$$${px}^2+qx-3,\mathrm{then}\frac{-(9a+3p)}{3b+q}=\mathrm{\_}\mathrm{\_}\mathrm{\_}\mathrm{\_}.$$

Answered by tanmay.chaudhury50@gmail.com last updated on 13/Jun/18

$$a{(-3)}^2+b(-3)+1=0$$$$9a-3b+1=0$$$$9p-3q-3=03p=q+1$$$$\frac{-(3b-1+q+1)}{3b+q}$$$$=-1$$

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