Question Number 37464 by bholachaudhary211@gamil.com last updated on 13/Jun/18
$$\mathrm{36}\boldsymbol{{x}}^{\mathrm{2}} \boldsymbol{{y}}^{\mathrm{2}} -\mathrm{42}\boldsymbol{{x}}^{\mathrm{3}} \boldsymbol{{y}}^{\mathrm{3}} +\mathrm{24}\boldsymbol{{x}}^{\mathrm{5}} \boldsymbol{{y}}^{\mathrm{4}} \\ $$
Commented by Joel579 last updated on 14/Jun/18
$$\mathrm{simplifying}? \\ $$$$\mathrm{6}{x}^{\mathrm{2}} {y}^{\mathrm{2}} \left(\mathrm{6}\:−\:\mathrm{7}{xy}\:+\:\mathrm{4}{x}^{\mathrm{3}} {y}^{\mathrm{2}} \right) \\ $$
Commented by $@ty@m last updated on 13/Jun/18
$${What}\:{to}\:{do}? \\ $$
Answered by faria3 last updated on 15/Jun/18
$$\mathrm{4}+\mathrm{4}=\mathrm{0} \\ $$
Commented by prof Abdo imad last updated on 15/Jun/18
$${correct}\:{in}\:{Z}/\mathrm{2}{Z}\:... \\ $$