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Question Number 37645 by Raj Singh last updated on 16/Jun/18

Answered by Rasheed.Sindhi last updated on 16/Jun/18

Both did (1/(12)) of work in 1 day. (4/(12))=(1/3) of work in 4 days Remaining part of work =1−(1/3)=(2/3) Ram did (2/3) of work in 20 days He can do whole work in 20×(3/2)=30 days He can do (1/(30)) of work in 1 day He can do (4/(30))=(2/(15)) of work in 4 days Shyam did (1/3)−(2/(15))=(1/5) of work in 4 days. He can do whole work in 4×5=20 days

$$\mathrm{Both}\:\mathrm{did}\:\:\frac{\mathrm{1}}{\mathrm{12}}\:\mathrm{of}\:\mathrm{work}\:\mathrm{in}\:\mathrm{1}\:\mathrm{day}. \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{\mathrm{4}}{\mathrm{12}}=\frac{\mathrm{1}}{\mathrm{3}}\:\mathrm{of}\:\mathrm{work}\:\mathrm{in}\:\mathrm{4}\:\mathrm{days} \\ $$$$\mathrm{Remaining}\:\mathrm{part}\:\mathrm{of}\:\mathrm{work}\:=\mathrm{1}−\frac{\mathrm{1}}{\mathrm{3}}=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$$\mathrm{Ram}\:\mathrm{did}\:\frac{\mathrm{2}}{\mathrm{3}}\:\mathrm{of}\:\mathrm{work}\:\mathrm{in}\:\mathrm{20}\:\mathrm{days} \\ $$$$\mathrm{He}\:\mathrm{can}\:\mathrm{do}\:\mathrm{whole}\:\mathrm{work}\:\mathrm{in}\:\mathrm{20}×\frac{\mathrm{3}}{\mathrm{2}}=\mathrm{30}\:\mathrm{days} \\ $$$$\mathrm{He}\:\mathrm{can}\:\mathrm{do}\:\frac{\mathrm{1}}{\mathrm{30}}\:\mathrm{of}\:\mathrm{work}\:\mathrm{in}\:\mathrm{1}\:\mathrm{day} \\ $$$$\mathrm{He}\:\mathrm{can}\:\mathrm{do}\:\frac{\mathrm{4}}{\mathrm{30}}=\frac{\mathrm{2}}{\mathrm{15}}\:\mathrm{of}\:\mathrm{work}\:\mathrm{in}\:\mathrm{4}\:\mathrm{days} \\ $$$$\mathrm{Shyam}\:\mathrm{did}\:\frac{\mathrm{1}}{\mathrm{3}}−\frac{\mathrm{2}}{\mathrm{15}}=\frac{\mathrm{1}}{\mathrm{5}}\:\mathrm{of}\:\mathrm{work}\:\mathrm{in}\:\mathrm{4}\:\mathrm{days}. \\ $$$$\mathrm{He}\:\mathrm{can}\:\mathrm{do}\:\mathrm{whole}\:\mathrm{work}\:\mathrm{in}\:\mathrm{4}×\mathrm{5}=\mathrm{20}\:\mathrm{days} \\ $$

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