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Question Number 37649 by Tinkutara last updated on 16/Jun/18

Answered by Rio Mike last updated on 16/Jun/18

yes the answer is (C) net induced charge on the sphere is zero.If charges can neither flow onto or off the spherical shell the net charge cannot change(0). and also because itcan not acquire or give up charge.

$$\mathrm{yes}\:\mathrm{the}\:\mathrm{answer}\:\mathrm{is}\:\left(\mathrm{C}\right)\:\mathrm{net}\:\mathrm{induced} \\ $$$$\mathrm{charge}\:\mathrm{on}\:\mathrm{the}\:\mathrm{sphere}\:\mathrm{is}\:\mathrm{zero}.\mathrm{If}\:\mathrm{charges} \\ $$$$\mathrm{can}\:\mathrm{neither}\:\mathrm{flow}\:\mathrm{onto}\:\mathrm{or}\:\mathrm{off}\:\mathrm{the}\: \\ $$$$\mathrm{spherical}\:\mathrm{shell}\:\mathrm{the}\:\mathrm{net}\:\mathrm{charge}\:\mathrm{cannot} \\ $$$$\mathrm{change}\left(\mathrm{0}\right). \\ $$$$\mathrm{and}\:\mathrm{also}\:\mathrm{because}\:\mathrm{itcan}\:\mathrm{not}\:\mathrm{acquire}\: \\ $$$$\mathrm{or}\:\mathrm{give}\:\mathrm{up}\:\mathrm{charge}. \\ $$$$ \\ $$

Commented by Tinkutara last updated on 16/Jun/18

Why not b?

Commented by Rio Mike last updated on 16/Jun/18

why will you suggest (b)?

$$\mathrm{why}\:\mathrm{will}\:\mathrm{you}\:\mathrm{suggest}\:\left(\mathrm{b}\right)? \\ $$

Commented by Rio Mike last updated on 16/Jun/18

To my own point of view sir Tinkutara if the shell can′t acquire or give up charge ..net charge cannot change..like i said its like a poker game ...you can play with your friends, money can only move around.some of you might lose money some might gain but the net change in money for all of you is zero. Begining=End (0)

$$\mathrm{To}\:\mathrm{my}\:\mathrm{own}\:\mathrm{point}\:\mathrm{of}\:\mathrm{view}\:\mathrm{sir}\: \\ $$$$\mathrm{Tinkutara}\:\mathrm{if}\:\mathrm{the}\:\mathrm{shell}\:\mathrm{can}'\mathrm{t}\:\mathrm{acquire}\:\mathrm{or} \\ $$$$\mathrm{give}\:\mathrm{up}\:\mathrm{charge}\:..\mathrm{net}\:\mathrm{charge}\:\mathrm{cannot}\: \\ $$$$\mathrm{change}..\mathrm{like}\:\mathrm{i}\:\mathrm{said}\:\mathrm{its}\:\mathrm{like}\:\mathrm{a}\:\mathrm{poker}\:\mathrm{game} \\ $$$$...\mathrm{you}\:\mathrm{can}\:\mathrm{play}\:\mathrm{with}\:\mathrm{your}\:\mathrm{friends}, \\ $$$$\mathrm{money}\:\mathrm{can}\:\mathrm{only}\:\mathrm{move}\:\mathrm{around}.\mathrm{some} \\ $$$$\mathrm{of}\:\mathrm{you}\:\mathrm{might}\:\mathrm{lose}\:\mathrm{money}\:\mathrm{some}\:\mathrm{might}\: \\ $$$$\mathrm{gain}\:\mathrm{but}\:\mathrm{the}\:\mathrm{net}\:\mathrm{change}\:\mathrm{in}\:\mathrm{money}\: \\ $$$$\mathrm{for}\:\mathrm{all}\:\mathrm{of}\:\mathrm{you}\:\mathrm{is}\:\mathrm{zero}. \\ $$$$\mathrm{Begining}=\mathrm{End}\:\left(\mathrm{0}\right) \\ $$

Commented by Tinkutara last updated on 16/Jun/18

Because electric field inside the sphere should also be 0.

Commented by Rio Mike last updated on 16/Jun/18

yes your right but i think c is the best answer

$$\mathrm{yes}\:\mathrm{your}\:\mathrm{right}\:\mathrm{but}\:\mathrm{i}\:\mathrm{think}\:\mathrm{c} \\ $$$$\mathrm{is}\:\mathrm{the}\:\mathrm{best}\:\mathrm{answer} \\ $$

Commented by Tinkutara last updated on 24/Jun/18

Can anyone confirm the answer please?

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