The distance S metres is given as a funtion f(t) where is time taken... if S = t^3 + t^2 + 4 find the velocity and acceleration


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Question Number 37972 by Rio Mike last updated on 20/Jun/18

$T h e d i s t a n c e S m e t r e s i s$ $g i v e n a s a f u n t i o n$ $f (t) w h e r e i s t i m e t a k e n . . .$ $i f S = t^{3} + t^{2} + 4$ $f i n d t h e v e l o c i t y a n d a c c e l e r a t i o n$
	Answered by Joel579 last updated on 20/Jun/18

	$s (t) = t^{3} + t^{2} + 4$ $v (t) = \frac{d s}{d t} = 3 t^{2} + 2 t$ $a (t) = \frac{d v}{d t} = 6 t$
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