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Question Number 38057 by ajfour last updated on 21/Jun/18
∫cos5x+cos4x1−2cos3xdx=?
Answered by tanmay.chaudhury50@gmail.com last updated on 21/Jun/18
∫sin3x(cos5x+coz4x)sin3x−sin6xdx∫sin3x(cos5x+cos4x)−2cos9x2sin3x2dx∫2sin3x2cos3x2×2cos9x2cosx2−2cos9x2sin3x2dx=−1×∫2cos3x2cosx2dx=−1×∫(cos2x+cosx)dx=−1×{sin2x2+sinx}+c
Commented by ajfour last updated on 21/Jun/18
VeryquickandrightSir.
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