tan α−tan β = 2tan θ asin α−bsin β = lsin θ express sin α, sin β in terms of 𝛉.


Question and Answers Forum

All Questions Topic List
Trigonometry Questions
Previous in All Question Next in All Question
Previous in Trigonometry Next in Trigonometry
Question Number 38288 by ajfour last updated on 23/Jun/18

$\tan α - \tan β = 2 \tan θ$ $a \sin α - b \sin β = l \sin θ$ $e x p r e s s \sin α, \sin β i n t e r m s o f θ .$
	Answered by tanmay.chaudhury50@gmail.com last updated on 24/Jun/18

	$t_{1} = t a n \frac{α}{2} t_{2} = t a n \frac{β}{2} p = t a n \frac{θ}{2}$ $\frac{2 t_{1}}{1 - t_{1}^{2}} - \frac{2 t_{2}}{1 - t_{2}^{2}} = \frac{4 p}{1 - p^{2}}$ $a \frac{2 t_{1}}{1 + t_{1}^{2}} - b \frac{2 t_{2}}{1 + t_{2}^{2}} = l \frac{2 p}{1 + p^{2}}$ $w a i t$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum