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Question Number 38289 by Tinkutara last updated on 23/Jun/18

Answered by tanmay.chaudhury50@gmail.com last updated on 23/Jun/18

$$centre(-g,-f)liesonax+by+d=0$$$$a(-g)+b(-f)+d=0$$$$\lambda (-g)-a(-f)+\mu g+k=0$$$$g(-a)+f(-b)+d=0$$$$g(-\lambda +\mu )+f\left(a\right)+k=0$$$$g(-a)+f(-b)=-d$$$$\frac{g}{\frac{d}{a}}+\frac{f}{\frac{d}{b}}=1$$$$\frac{g}{\frac{k}{\lambda -\mu }}+\frac{f}{\frac{k}{a}}=1$$$$\frac{d}{a}=\frac{k}{\lambda -\mu }and\frac{d}{b}=\frac{k}{a}$$$$\frac{d}{a}=\frac{ad}{b(\lambda -\mu )}$$$$$$$$b(\lambda -\mu )=a^2$$$$\lambda -\mu =\frac{a^2}{b}plscheck$$$$$$

Commented by Tinkutara last updated on 23/Jun/18

$$\lambda +\mu istobefound,Sir.$$

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