Find the area common to min{[x], [y] } =2 and max{[x], [y] } =4 . [x] denotes the greatest integer less than or equal to x.


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Question Number 38568 by ajfour last updated on 27/Jun/18

$F i n d t h e a r e a c o m m o n t o$ $m i n {[x], [y]} = 2 a n d$ $m a x {[x], [y]} = 4 .$ $[x] d e n o t e s t h e g r e a t e s t i n t e g e r$ $l e s s t h a n o r e q u a l t o x .$
Commented by ajfour last updated on 27/Jun/18

$R i g h t s k e t c h, r i g h t a n s w e r S i r .$ $F i n d a r e a b o u n d e d b y$ $m i n {∣ x ∣, ∣ y ∣} = 2$ $m a x {∣ x ∣, ∣ y ∣} = 4$
Commented by MrW3 last updated on 27/Jun/18

Commented by MrW3 last updated on 27/Jun/18

$c o m m o n a r e a = 2$
Commented by tanmay.chaudhury50@gmail.com last updated on 27/Jun/18

Commented by tanmay.chaudhury50@gmail.com last updated on 27/Jun/18

Commented by tanmay.chaudhury50@gmail.com last updated on 27/Jun/18

$a r e a = 8^{2} - 4^{2} = 64 - 16 = 48$
Commented by tanmay.chaudhury50@gmail.com last updated on 27/Jun/18

$a r e a f o r m e d b y ∣ x ∣= 4 a n d ∣ y ∣= 4 i s 8 \times 8 = 64$ $a r e a f o r m e d b y ∣ x ∣= 2 a n d ∣ y ∣= 2 i s = 4 \times 4 = 16$ $s o = a r e a r e q u i r e d 64 - 16 = 48$
Commented by tanmay.chaudhury50@gmail.com last updated on 27/Jun/18

Commented by ajfour last updated on 27/Jun/18

$m i n {}, m a x {} h a s a m e a n i n g .$
Commented by tanmay.chaudhury50@gmail.com last updated on 27/Jun/18

$y o u s o l v e t h e q u e s t i o n . . .$
Commented by MrW3 last updated on 27/Jun/18

$a r e a b o u n d e d b y$ $m i n {[x], [y]} = 2$ $m a x {[x], [y]} = 4$ $i s 8 .$ $a r e a b o u n d e d b y$ $m i n {∣ x ∣, ∣ y ∣} = 2$ $m a x {∣ x ∣, ∣ y ∣} = 4$ $i s 16 .$
Commented by ajfour last updated on 27/Jun/18

$A r e a f o r t h e s e c o n d o n e i s 16 .$
Commented by MrW3 last updated on 27/Jun/18

${y o u}^{'} r r i g h t .$
Commented by MrW3 last updated on 27/Jun/18

Commented by ajfour last updated on 27/Jun/18

$G r e a t, S i r . y o u a r e f a s t .$
Commented by ajfour last updated on 28/Jun/18

$T o o G o o d S i r .$
Commented by MrW3 last updated on 28/Jun/18

Commented by MrW3 last updated on 28/Jun/18

$t h e p i n k c o l o r a r e a i s a l s o b o u n d e d$ $a r e a w h i c h i s 64 - 16 = 48 .$
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