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Question Number 38641 by maxmathsup by imad last updated on 27/Jun/18

$$calculate{lim}_{n\to +\mathrm{\infty }}\frac{1+2^3+3^3+....+n^3}{1+2^4+3^4+...+n^4}.$$

Commented by abdo mathsup 649 cc last updated on 28/Jun/18

$$theQisfind\sum _{n=1}^{\mathrm{\infty }}\frac{1+2^3+3^3+...+n^3}{1+2^4+3^4+...+n^4}$$

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