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Question Number 38696 by Sr@2004 last updated on 28/Jun/18

Answered by tanmay.chaudhury50@gmail.com last updated on 28/Jun/18

(1/(b+c))+(1/(c+a))=(2/(a+b)) (1/(b+c))−(1/(a+b))=(1/(a+b))−(1/(c+a)) ((a+b−b−c)/((a+b)(b+c)))=((c+a−a−b)/((a+b)(c+a))) ((a−c)/(b+c))=((c−b)/(c+a)) a^2 −c^2 =c^2 −b^2 a^2 +b^2 =2c^2 proved pls correct the question

1b+c+1c+a=2a+b1b+c−1a+b=1a+b−1c+aa+b−b−c(a+b)(b+c)=c+a−a−b(a+b)(c+a)a−cb+c=c−bc+aa2−c2=c2−b2a2+b2=2c2provedplscorrectthequestion

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