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Question Number 3877 by Rasheed Soomro last updated on 23/Dec/15

What is the area of  overlapping  region of two circles having radii  r_1  and r_2  when the distance between  their centres is  c, given that r_1 +r_2 >c.

Whatistheareaofoverlapping regionoftwocircleshavingradii r1andr2whenthedistancebetween theircentresisc,giventhatr1+r2>c.

Commented byprakash jain last updated on 24/Dec/15

I will make the correction.  The above procedure is for centers on different  side of common chord.

Iwillmakethecorrection. Theaboveprocedureisforcentersondifferent sideofcommonchord.

Commented byprakash jain last updated on 24/Dec/15

Common chord AB  center O_1  and O_2   O_1 O_2  cuts AB at X  ∠AO_1 X=α  ∠AO_2 X=β  AB=2r_1 sin  α=2r_2 sin β  O_1 X=r_1 cos α,    XO_2 =r_2 cos β  r_1 cos α+r_2 cos β=c  area of △AO_1 B=(1/2)AB×O_1 X=r_1 ^2 cos αsin α  area of △AO_2 B=(1/2)AB×O_2 X=r_2 ^2 cos βsin β  area of overlapin portion=area of  circle segment − area of triangle  Area of overlapping portion on side of  circle with radius r_1 =αr_1 −area △AO_1 B       X=(1/2)αr_1 ^2 −(1/2)r_1 ^2 sin 2α     ...(1)  Area of overlapping portion on side of  circle with radius r_2 =βr_2 −area △AO_2 B       Y=(1/2)βr_2 ^2 −(1/2)r_2 ^2 sin 2β      ...(2)  Next step is to find α, β   r_1 cos α+r_2 cos β=c⇒r_1 ^2 cos^2 α=c^2 −2cr_2 cos β+r_2 ^2 cos^2 β  r_1 sin  α=r_2 sin β⇒r_1 ^2 cos^2 α=r_1 ^2 −r_2 ^2 +r_2 ^2 cos^2 β  c^2 −2cr_2 cos β+r_2 ^2 cos^2 β=r_1 ^2 −r_2 ^2 +r_2 ^2 cos^2 β  cos β=((c^2 −r_1 ^2 +r_2 ^2 )/(2cr_2 ))          ...(3)  cos α=((c^2 −r_2 ^2 +r_1 ^2 )/(2cr_2 ))         ...(4)    Total overlapping area is X+Y as given  in equation (1) and (2). value of α and β  given in (3) and (4).

CommonchordAB centerO1andO2 O1O2cutsABatX AO1X=α AO2X=β AB=2r1sinα=2r2sinβ O1X=r1cosα,XO2=r2cosβ r1cosα+r2cosβ=c areaofAO1B=12AB×O1X=r12cosαsinα areaofAO2B=12AB×O2X=r22cosβsinβ areaofoverlapinportion=areaof circlesegmentareaoftriangle Areaofoverlappingportiononsideof circlewithradiusr1=αr1areaAO1B X=12αr1212r12sin2α...(1) Areaofoverlappingportiononsideof circlewithradiusr2=βr2areaAO2B Y=12βr2212r22sin2β...(2) Nextstepistofindα,β r1cosα+r2cosβ=cr12cos2α=c22cr2cosβ+r22cos2β r1sinα=r2sinβr12cos2α=r12r22+r22cos2β c22cr2cosβ+r22cos2β=r12r22+r22cos2β cosβ=c2r12+r222cr2...(3) cosα=c2r22+r122cr2...(4) TotaloverlappingareaisX+Yasgiven inequation(1)and(2).valueofαandβ givenin(3)and(4).

Commented byYozzii last updated on 23/Dec/15

Isn′t the area of a sector of a circle of  radius r produced by angle α given by  (1/2)r^2 α?   rα gives arc length no?   Is the method different if both   centres are on the same side of the  commom chord?

Isnttheareaofasectorofacircleof radiusrproducedbyangleαgivenby 12r2α?rαgivesarclengthno? Isthemethoddifferentifboth centresareonthesamesideofthe commomchord?

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