Math Question and Answers


Question and Answers Forum

All Questions Topic List
Algebra Questions
Previous in All Question Next in All Question
Previous in Algebra Next in Algebra
Question Number 38825 by Sr@2004 last updated on 30/Jun/18

Commented by kunal1234523 last updated on 30/Jun/18

$s i r S r @ 2004 y o u c a n w r i t e h e r e v e r y e a s i l y .$
Commented by Sr@2004 last updated on 30/Jun/18

$p l e a s e s o l v e i t .$
Commented by NECx last updated on 30/Jun/18

$p l e a s e t y p e i t i n s t e a d$
Commented by Sr@2004 last updated on 30/Jun/18

$I c a n n o t u n d e r s t a n d$
	Answered by kunal1234523 last updated on 30/Jun/18

	$(x + z) : (y + z) = (\frac{x}{y} + 2) : (\frac{y}{x} + 2)$ $\frac{x + z}{y + z} = \frac{(x + 2 y) x}{(y + 2 x) y}$ $(x + z) (y^{2} + 2 x y) = (y + z) (x^{2} + 2 x y)$ ${x y}^{2} + 2 x^{2} y + y^{2} z + 2 x y z = x^{2} y + 2 {x y}^{2} + x^{2} z + 2 x y z$ $x^{2} y - {x y}^{2} = x^{2} z - y^{2} z$ ${x y}^{2} - y^{2} z = x^{2} y - x^{2} z$ $y^{2} (x - z) = x^{2} (y - z)$ $\frac{x - z}{y - z} = \frac{x^{2}}{y^{2}}$ $(x - z) : (y - z) = x^{2} : y^{2} p r o v e d$
	Commented by Sr@2004 last updated on 30/Jun/18

	$t h a n k y o u$
	Commented by Sr@2004 last updated on 30/Jun/18

	$b u t p l e a s e s o l v e i n a n o t h e r w a y s i r .$
	Commented by kunal1234523 last updated on 30/Jun/18

	$i n w h i c h w a y$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum