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Question Number 38849 by behi83417@gmail.com last updated on 30/Jun/18

Commented by behi83417@gmail.com last updated on 30/Jun/18

$$\mathit{r}\mathit{a}\mathit{w}\mathit{i}\mathit{d}\mathit{e}\mathit{a}\mathit{t}\mathit{o}\mathit{m}\mathit{r}\mathit{A}\mathit{j}\mathit{f}\mathit{o}\mathit{u}\mathit{r}!$$$${\mathit{a}}^2={\mathit{x}}^2+{\mathit{t}}^2,\mathit{z}=\mathit{c}.\mathit{c}\mathit{o}\mathit{s}\mathit{\theta }$$$${\mathit{b}}^2={\mathit{x}}^2+{\mathit{y}}^2,\mathit{x}=1-\mathit{c}.\mathit{c}\mathit{o}\mathit{s}\mathit{\theta }$$$${\mathit{c}}^2={\mathit{y}}^2+{\mathit{z}}^2,\mathit{t}=1-\mathit{c}.\mathit{s}\mathit{i}\mathit{n}\mathit{\theta }$$$${\mathit{d}}^2={\mathit{z}}^2+{\mathit{t}}^2,\mathit{y}=\mathit{c}.\mathit{s}\mathit{i}\mathit{n}\mathit{\theta }$$$$---------------$$$${\mathit{a}}^2+{\mathit{c}}^2={\mathit{b}}^2+{\mathit{d}}^2$$

Answered by ajfour last updated on 30/Jun/18

$$ultimatelyalloftheseleadsto$$$$(if\mathit{c}\cot \theta =x)$$$${\mathit{x}}^2({\mathit{x}}^2+{\mathit{c}}^2)={(\mathit{x}+\mathit{c})}^2.$$

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