Find the equation of the perpendicular bisector of the line segment joining the points (1,3) and (5,1)


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Question Number 38880 by Rio Mike last updated on 30/Jun/18

$F i n d t h e e q u a t i o n o f t h e p e r p e n d i c u l a r$ $b i s e c t o r o f t h e l i n e s e g m e n t j o i n i n g$ $t h e p o i n t s (1, 3) a n d (5, 1)$
	Answered by MrW3 last updated on 30/Jun/18

	$e q n o f l i n e j o i n i n g (1, 3) a n d (5, 1) :$ $\frac{y - 1}{3 - 1} = \frac{x - 5}{1 - 5}$ $y = - \frac{1}{2} (x - 5) + 1 = - \frac{1}{2} x + \frac{7}{2}$ $m i d p o i n t o f (1, 3) a n d (5, 1) :$ $(3, 2)$ $e q n . o f p e r p e n d i c u l a r b i s e c t o r :$ $\frac{y - 2}{x - 3} = - \frac{1}{- \frac{1}{2}} = 2$ $\Rightarrow y = 2 x - 4$
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