Question and Answers Forum

All Questions      Topic List

Differentiation Questions

Previous in All Question      Next in All Question      

Previous in Differentiation      Next in Differentiation      

Question Number 38905 by Raj Singh last updated on 01/Jul/18

Answered by MrW3 last updated on 01/Jul/18

(a/(sin A))=(b/(sin B))=(c/(sin C))=k (constant) let dA =little change in angle A B=180−C−A ⇒dB=−dA a=k sin A da=k cos A dA ⇒(da/(cos A))=k dA b=k sin B db=k cos B dB=−k cos B dA ⇒(db/(cos B))=−k dA ⇒(da/(cos A))+(db/(cos B))=k dA−k dA=0

asinA=bsinB=csinC=k(constant)letdA=littlechangeinangleAB=180−C−A⇒dB=−dAa=ksinAda=kcosAdA⇒dacosA=kdAb=ksinBdb=kcosBdB=−kcosBdA⇒dbcosB=−kdA⇒dacosA+dbcosB=kdA−kdA=0

Terms of Service

Privacy Policy

Contact: info@tinkutara.com