A wave has a wavelength of 1.5m, calculate the phase angle between a point 0.25m from the peak of the wave and another point 1m further along the same peak.


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Question Number 38924 by NECx last updated on 01/Jul/18

$A w a v e h a s a w a v e l e n g t h o f 1.5 m,$ $c a l c u l a t e t h e p h a s e a n g l e b e t w e e n$ $a p o i n t 0.25 m f r o m t h e p e a k o f t h e$ $w a v e a n d a n o t h e r p o i n t 1 m f u r t h e r$ $a l o n g t h e s a m e p e a k .$
	Answered by tanmay.chaudhury50@gmail.com last updated on 01/Jul/18

	$ϕ_{1} = \frac{2 Π x}{λ} = \frac{2 Π \times 0.25}{1.5} = \frac{2 Π \times 25 \times 10}{100 \times 15} = \frac{Π}{3}$ $\emptyset_{2} = \frac{2 Π x}{λ} = \frac{2 Π \times 1}{1.5} = \frac{4 Π}{3}$ $△ ϕ = \frac{4 Π}{3} - \frac{Π}{3} = Π$
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