Question and Answers Forum

All Questions      Topic List

Trigonometry Questions

Previous in All Question      Next in All Question      

Previous in Trigonometry      Next in Trigonometry      

Question Number 39028 by maxmathsup by imad last updated on 01/Jul/18

1) calculate  A=cos((π/7)).cos(((2π)/7)).cos(((3π)/7))  2) calculate B =tan((π/7)).tan(((2π)/7)).tan(((3π)/7)).

$$\left.\mathrm{1}\right)\:{calculate}\:\:{A}={cos}\left(\frac{\pi}{\mathrm{7}}\right).{cos}\left(\frac{\mathrm{2}\pi}{\mathrm{7}}\right).{cos}\left(\frac{\mathrm{3}\pi}{\mathrm{7}}\right) \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:{B}\:={tan}\left(\frac{\pi}{\mathrm{7}}\right).{tan}\left(\frac{\mathrm{2}\pi}{\mathrm{7}}\right).{tan}\left(\frac{\mathrm{3}\pi}{\mathrm{7}}\right). \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 02/Jul/18

A×2sin(Π/7)=2sin(Π/7)cos(Π/7)cos((2Π)/7)cos((3Π)/7)  A×2sin(Π/7)=sin((2Π)/7)cos((2Π)/7)cos((3Π)/7)  A×2^2 sin(Π/7)=sin((4Π)/7)cos((3Π)/7)  A×2^3 sin(Π/7)=2sin((4Π)/7)cos((3Π)/7)  A×2^3 sin(Π/7)=sinΠ+sin(Π/7)  A×2^3 sin(Π/7)=sin(Π/7)  A=(1/8)

$${A}×\mathrm{2}{sin}\frac{\Pi}{\mathrm{7}}=\mathrm{2}{sin}\frac{\Pi}{\mathrm{7}}{cos}\frac{\Pi}{\mathrm{7}}{cos}\frac{\mathrm{2}\Pi}{\mathrm{7}}{cos}\frac{\mathrm{3}\Pi}{\mathrm{7}} \\ $$$${A}×\mathrm{2}{sin}\frac{\Pi}{\mathrm{7}}={sin}\frac{\mathrm{2}\Pi}{\mathrm{7}}{cos}\frac{\mathrm{2}\Pi}{\mathrm{7}}{cos}\frac{\mathrm{3}\Pi}{\mathrm{7}} \\ $$$${A}×\mathrm{2}^{\mathrm{2}} {sin}\frac{\Pi}{\mathrm{7}}={sin}\frac{\mathrm{4}\Pi}{\mathrm{7}}{cos}\frac{\mathrm{3}\Pi}{\mathrm{7}} \\ $$$${A}×\mathrm{2}^{\mathrm{3}} {sin}\frac{\Pi}{\mathrm{7}}=\mathrm{2}{sin}\frac{\mathrm{4}\Pi}{\mathrm{7}}{cos}\frac{\mathrm{3}\Pi}{\mathrm{7}} \\ $$$${A}×\mathrm{2}^{\mathrm{3}} {sin}\frac{\Pi}{\mathrm{7}}={sin}\Pi+{sin}\frac{\Pi}{\mathrm{7}} \\ $$$${A}×\mathrm{2}^{\mathrm{3}} {sin}\frac{\Pi}{\mathrm{7}}={sin}\frac{\Pi}{\mathrm{7}} \\ $$$${A}=\frac{\mathrm{1}}{\mathrm{8}} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com