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Question Number 39028 by maxmathsup by imad last updated on 01/Jul/18

1) calculate  A=cos((π/7)).cos(((2π)/7)).cos(((3π)/7))  2) calculate B =tan((π/7)).tan(((2π)/7)).tan(((3π)/7)).

1)calculateA=cos(π7).cos(2π7).cos(3π7)2)calculateB=tan(π7).tan(2π7).tan(3π7).

Answered by tanmay.chaudhury50@gmail.com last updated on 02/Jul/18

A×2sin(Π/7)=2sin(Π/7)cos(Π/7)cos((2Π)/7)cos((3Π)/7)  A×2sin(Π/7)=sin((2Π)/7)cos((2Π)/7)cos((3Π)/7)  A×2^2 sin(Π/7)=sin((4Π)/7)cos((3Π)/7)  A×2^3 sin(Π/7)=2sin((4Π)/7)cos((3Π)/7)  A×2^3 sin(Π/7)=sinΠ+sin(Π/7)  A×2^3 sin(Π/7)=sin(Π/7)  A=(1/8)

A×2sinΠ7=2sinΠ7cosΠ7cos2Π7cos3Π7A×2sinΠ7=sin2Π7cos2Π7cos3Π7A×22sinΠ7=sin4Π7cos3Π7A×23sinΠ7=2sin4Π7cos3Π7A×23sinΠ7=sinΠ+sinΠ7A×23sinΠ7=sinΠ7A=18

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