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Question Number 39174 by jasno91 last updated on 03/Jul/18

Answered by MrW3 last updated on 03/Jul/18

let a and b be the diagonals P=4(√(((a/2))^2 +((b/2))^2 )) P=2(√(a^2 +b^2 )) 10=2(√(3^2 +b^2 )) 100=4(9+b^2 ) 25=9+b^2 ⇒b=4=length of the other diagonal

letaandbbethediagonalsP=4(a2)2+(b2)2P=2a2+b210=232+b2100=4(9+b2)25=9+b2⇒b=4=lengthoftheotherdiagonal

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