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Question Number 39231 by LX Z last updated on 04/Jul/18
(sin−1x)2+(sin−1y)2+2(sin−1x)(sin−1y)=π2,thenx2+y2isequalto?
Answered by tanmay.chaudhury50@gmail.com last updated on 04/Jul/18
a=sin−1xb=sin−1ya2+2ab+b2=∏2a+b=Πsin−1x+sin−1y=Πsin−1x=Π−sin−1ya+b=Πsina=sin(Π−b)sina=sinba=ba+b=Πa=Π2b=Π2sin−1x=Π2x=1sin−1y=Π2y=1x2+y2=2plscheck
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