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Question Number 39231 by LX Z last updated on 04/Jul/18

(sin^(−1) x)^2 +  (sin^(−1) y)^2 +  2(sin^(−1) x)  (sin^(−1) y)= π^2 ,then x^2 +y^2  is equal to?

(sin1x)2+(sin1y)2+2(sin1x)(sin1y)=π2,thenx2+y2isequalto?

Answered by tanmay.chaudhury50@gmail.com last updated on 04/Jul/18

a=sin^(−1) x    b=sin^(−1) y       a^2 +2ab+b^2 =Π^2   a+b=Π  sin^(−1) x+sin^(−1) y=Π  sin^(−1) x=Π−sin^(−1) y  a+b=Π  sina=sin(Π−b)  sina=sinb  a=b     a+b=Π   a=(Π/2)     b=(Π/2)  sin^(−1) x=(Π/2)    x=1  sin^(−1) y=(Π/2)    y=1  x^2 +y^2 =2  pls check

a=sin1xb=sin1ya2+2ab+b2=2a+b=Πsin1x+sin1y=Πsin1x=Πsin1ya+b=Πsina=sin(Πb)sina=sinba=ba+b=Πa=Π2b=Π2sin1x=Π2x=1sin1y=Π2y=1x2+y2=2plscheck

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