Question and Answers Forum

All Questions      Topic List

Differentiation Questions

Previous in All Question      Next in All Question      

Previous in Differentiation      Next in Differentiation      

Question Number 39709 by Raj Singh last updated on 10/Jul/18

Commented by tanmay.chaudhury50@gmail.com last updated on 10/Jul/18

$$whatisthemeaningof{T}^3{T}^{\prime }$$

Answered by tanmay.chaudhury50@gmail.com last updated on 10/Jul/18

$$letpointTisct,\frac{c}{t}$$$$eqnofnormal(y-\frac{c}{t})=(-\frac{1}{m})(x-ct)$$$$x\frac{dy}{dx}+y=0so\frac{dy}{dx}=\frac{-y}{x}hencem=\frac{-\frac{c}{t}}{ct}$$$$m=\frac{-1}{t^2}so\frac{-1}{m}=t^2$$$$sonormaleqn(y-\frac{c}{t})=\left(t^2\right)(x-ct)$$$$nowlet{T}^{\prime }=({ct}_1,\frac{c}{t_1})$$$$(\frac{c}{t_1}-\frac{c}{t})=t^2({ct}_1-ct)$$$$\left(\frac{ct-{ct}_1}{{tt}_1}\right)-t^2({ct}_1-ct)=0ihavedonesomemistske$$$$edited$$$$$$$$(ct-{ct}_1)(\frac{1}{{tt}_1}+t^2)=0$$$$t^3{t}_1+1=0so{t}^3{t}_1=-1$$$$pointT(ct,\frac{c}{t})andpoint{T}^{\prime }(\frac{c}{-t^3},\frac{-{ct}^3}{})$$

Commented by Raj Singh last updated on 10/Jul/18

$$howyoufind(ct,c/t)$$$$$$

Commented by tanmay.chaudhury50@gmail.com last updated on 10/Jul/18

$$ct,\frac{c}{t}isapointliesonthecurve...parsmetric$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com