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Question Number 40012 by rahul 19 last updated on 15/Jul/18

Answered by ajfour last updated on 15/Jul/18

$${\left(mg\right)}_{max}=\frac{3Mg}{5}+\frac{0.6\left(4Mg\right)}{5}$$$$\Rightarrow m_{max}=30kg+24kg=54kg$$$${\left(mg\right)}_{min}=\frac{3Mg}{5}-\frac{0.6\left(4Mg\right)}{5}$$$$\Rightarrow m_{min}=30kg-24kg=6kg.$$

Commented by rahul 19 last updated on 15/Jul/18

Thank you sir ����

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