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Question Number 40058 by rahul 19 last updated on 15/Jul/18

	Answered by rahul 19 last updated on 16/Jul/18

	$By Energy conservation$ $10.10.3 + \frac{1}{2} . 100 . {(1)}^{2} = \frac{1}{2} . 10 . v^{2}$ $\Rightarrow v = \sqrt{70} m / s$ ${What}^{'} s wrong in this ?$
	Commented by rahul 19 last updated on 16/Jul/18

	$ok sir .$
	Commented by MrW3 last updated on 15/Jul/18

	$y o u r a n s w e r i s c o r r e c t, i f t h e r e i s$ $n o f r i c t i o n b e t w e e n r i n g a n d r o d .$ $b u t i n t h e q u e s t i o n t h e r e i s f r i c t i o n,$ $s o t h e v e l o c i t y m u s t b e l e s s t h a n \sqrt{70} m / s,$ $s i n c e a p a r t o f e n e r g y i s l o s t d u e t o$ $f r i c t i o n .$
	Answered by tanmay.chaudhury50@gmail.com last updated on 15/Jul/18

	$m g h + \frac{1}{2} k (x_{2}^{2} - x_{1}^{2}) = \frac{1}{2} {m v}^{2}$ $10.10.3 + \frac{1}{2} . 100 . (5^{2} - 4^{2}) = \frac{1}{2} . 10 . v^{2}$ $300 + 450 = 5 v^{2}$ $v = \sqrt{150} = 12.25$
	Commented by rahul 19 last updated on 15/Jul/18
	Ans. given is 10m/s.
	Commented by tanmay.chaudhury50@gmail.com last updated on 15/Jul/18

	$i f 4 m i s t h e n a t u r a l l e n g t h o f s p r i n g t h e n$ $e q n i s$ $10.10.3 + \frac{1}{2} . 100 . {(5 - 4)}^{2} = \frac{1}{2} . 10 . v^{2}$ $v = \sqrt{70}$
	Commented by rahul 19 last updated on 15/Jul/18

	$yes sir, i am also getting same ans .$ $does it mean ans . given in book is$ $wrong ?$
	Commented by tanmay.chaudhury50@gmail.com last updated on 15/Jul/18

	$y e s i t h i n k s o$
	Commented by tanmay.chaudhury50@gmail.com last updated on 15/Jul/18

	Commented by tanmay.chaudhury50@gmail.com last updated on 15/Jul/18

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