Solve 4x^2 −8x−3=0


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Question Number 40212 by KMA last updated on 17/Jul/18

$S o l v e 4 x^{2} - 8 x - 3 = 0$
Commented by MJS last updated on 17/Jul/18

${a x}^{2} + b x + c = 0$ $x = - \frac{b}{2 a} \pm \frac{\sqrt{b^{2} - 4 a c}}{2 a}$ $x^{2} + p x + q = 0$ $x = - \frac{p}{2} \pm \frac{\sqrt{p^{2} - 4 q}}{2}$
	Answered by tanmay.chaudhury50@gmail.com last updated on 17/Jul/18

	${(2 x)}^{2} - 2.2 x . 2 + 4 - 7 = 0$ ${(2 x - 2)}^{2} = 7$ $2 x = 2 \pm \sqrt{7}$ $x = \frac{2 \pm \sqrt{7}}{2}$
	Answered by Rio Mike last updated on 17/Jul/18

	$a = 4, b = - 8, c = - 3$ $x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $x = \frac{8 \pm \sqrt{64 - 12}}{8}$ $x = \frac{8 \pm 7.2}{8}$ $x = \frac{8 + 7.2}{8} o r \frac{8 - 7.2}{8}$
	Commented by tanmay.chaudhury50@gmail.com last updated on 17/Jul/18

	$c h e c k t h e v a l u e o f 4 a c$
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