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Question Number 40231 by Raj Singh last updated on 17/Jul/18

Answered by tanmay.chaudhury50@gmail.com last updated on 17/Jul/18

$$\frac{cosA-sinA+1}{cosA+sinA-1}$$$$a=sinAb=cosA{a}^2+b^2=1$$$$\frac{(b-a+1)(b+a+1)}{(b+a-1)(b+a+1)}$$$$=\frac{{(b+1)}^2-a^2}{{(b+a)}^2-1}$$$$=\frac{b^2+2b+1-a^2}{b^2+2ab+a^2-1}$$$$=\frac{b^2+2b+b^2}{2ab}$$$$=\frac{2b(b+1)}{2ab}$$$$=\frac{b+1}{a}=\frac{b}{a}+\frac{1}{a}=cotA+cosecA$$$$$$$$$$$$$$

Commented by Raj Singh last updated on 17/Jul/18

$$thankyou$$

Commented by tanmay.chaudhury50@gmail.com last updated on 17/Jul/18

$$itsok....$$

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