Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 40610 by ajfour last updated on 24/Jul/18

Answered by MJS last updated on 25/Jul/18

$$\mathrm{easy}\mathrm{to}\mathrm{understand}\mathrm{with}4+1\mathrm{spheres}$$$$\mathrm{let}\mathrm{radius}\mathrm{of}\mathrm{the}\mathrm{spheres}=1$$$$\mathrm{the}\mathrm{angle}\mathrm{of}\mathrm{the}\mathrm{side}\mathrm{of}\mathrm{the}\mathrm{cone}\mathrm{is}45°$$$$\mathrm{its}\mathrm{radius}=\mathrm{height}\mathrm{is}1+2\sqrt{2}$$$$(\mathrm{cut}\mathrm{through}\mathrm{the}\mathrm{centers}\mathrm{of}2\mathrm{opposite}\mathrm{bottom}$$$$\mathrm{spheres}\mathrm{and}\mathrm{the}\mathrm{top}\mathrm{sphere},{\mathrm{it}}^{\prime }\mathrm{s}\mathrm{easy}\mathrm{to}\mathrm{see})$$$$\mathrm{volume}=\frac{25+22\sqrt{2}}{3}\pi$$$$$$$$v\left(R\right)=\frac{25+22\sqrt{2}}{3}\pi R^3$$$$$$$$\mathrm{now}\mathrm{someone}\mathrm{please}\mathrm{try}\mathrm{with}3+1\mathrm{and}5+1\mathrm{spheres}!$$

Commented by ajfour last updated on 25/Jul/18

Commented by ajfour last updated on 25/Jul/18

$$YesSir,correctanswer.$$$$V=\frac{{(1+2\sqrt{2})}^3\pi R^3}{3}.$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com