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Question Number 40667 by Tawa1 last updated on 25/Jul/18

find the value  lim_(x→0)  g(x)  must have, if g complies the statement   about limit. Suppose   lim_(x→ −4)   [x lim_(x→0)   g(x)]  =  2

$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\mathrm{g}\left(\mathrm{x}\right)\:\:\mathrm{must}\:\mathrm{have},\:\mathrm{if}\:\mathrm{g}\:\mathrm{complies}\:\mathrm{the}\:\mathrm{statement}\: \\ $$$$\mathrm{about}\:\mathrm{limit}.\:\mathrm{Suppose}\:\:\:\underset{{x}\rightarrow\:−\mathrm{4}} {\mathrm{lim}}\:\:\left[\mathrm{x}\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\mathrm{g}\left(\mathrm{x}\right)\right]\:\:=\:\:\mathrm{2} \\ $$

Commented by tanmay.chaudhury50@gmail.com last updated on 26/Jul/18

mobile handset does not show a few   portion of problem ...so pls check ...repost the  problem or  check my answer...

$${mobile}\:{handset}\:{does}\:{not}\:{show}\:{a}\:{few}\: \\ $$$${portion}\:{of}\:{problem}\:...{so}\:{pls}\:{check}\:...{repost}\:{the} \\ $$$${problem}\:{or}\:\:{check}\:{my}\:{answer}... \\ $$

Commented by Joel578 last updated on 26/Jul/18

have u tried to scroll sideways?

$${have}\:{u}\:{tried}\:{to}\:{scroll}\:{sideways}? \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 25/Jul/18

let lim_(x→0) g(x) =A  where A is independent of x  lim_(x→−4)  [xlim_(x→0) g(x)] =2  given  lim_(x→−4)  A.x=  2  so −4A=2  A=((−1)/2)   hence lim_(x→0) g(x)=((−1)/2)   pls check...

$${let}\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}{g}\left({x}\right)\:={A} \\ $$$${where}\:{A}\:{is}\:{independent}\:{of}\:{x} \\ $$$$\underset{{x}\rightarrow−\mathrm{4}} {\mathrm{lim}}\:\left[{x}\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}{g}\left({x}\right)\right]\:=\mathrm{2}\:\:{given} \\ $$$$\underset{{x}\rightarrow−\mathrm{4}} {\mathrm{lim}}\:{A}.{x}=\:\:\mathrm{2} \\ $$$${so}\:−\mathrm{4}{A}=\mathrm{2} \\ $$$${A}=\frac{−\mathrm{1}}{\mathrm{2}}\:\:\:{hence}\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}{g}\left({x}\right)=\frac{−\mathrm{1}}{\mathrm{2}}\:\:\:{pls}\:{check}... \\ $$

Commented by Tawa1 last updated on 26/Jul/18

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

Commented by tanmay.chaudhury50@gmail.com last updated on 26/Jul/18

thank you,that means i have reached the _   destination...

$${thank}\:{you},{that}\:{means}\:{i}\:{have}\:{reached}\:{the}\:_{} \\ $$$${destination}... \\ $$$$ \\ $$

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