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Question Number 40763 by Cheyboy last updated on 27/Jul/18

Answered by MJS last updated on 27/Jul/18

$$x=y=z=1$$

Commented by Cheyboy last updated on 27/Jul/18

$$sir,showworking$$$$$$

Commented by MJS last updated on 27/Jul/18

$$\mathrm{this}\mathrm{is}\mathrm{plain}\mathrm{to}\mathrm{see},{\mathrm{I}}^{\prime }\mathrm{ll}\mathrm{try}\mathrm{to}\mathrm{find}\mathrm{out}\mathrm{if}\mathrm{there}$$$$\mathrm{are}\mathrm{more}\mathrm{solutions}...$$

Commented by Cheyboy last updated on 27/Jul/18

$$Oksirthankyou$$

Answered by MJS last updated on 27/Jul/18

$$\mathrm{we}\mathrm{have}\mathrm{only}2\mathrm{equations}\mathrm{for}3\mathrm{unknowns}$$$$\Rightarrow \mathrm{the}\mathrm{number}\mathrm{of}\mathrm{solutions}\mathrm{is}\mathrm{\infty }$$

Commented by MJS last updated on 27/Jul/18

$$\mathrm{choose}\mathrm{any}\mathrm{value}\mathrm{for}x\ne 0\mathrm{and}{\mathrm{it}}^{\prime }\mathrm{s}\mathrm{possible}$$$$\mathrm{to}\mathrm{solve}\mathrm{for}y,z\in \mathbb{R}$$$$\left(\mathrm{there}\mathrm{might}\mathrm{also}\mathrm{be}\mathrm{complex}\mathrm{solutions}\right)$$

Commented by Cheyboy last updated on 27/Jul/18

$$Thankyousir$$

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