Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 40814 by behi83417@gmail.com last updated on 27/Jul/18

Commented by MrW3 last updated on 27/Jul/18

x=0, y=1 or x=1, y=0

x=0,y=1orx=1,y=0

Commented by math khazana by abdo last updated on 28/Jul/18

from the equality we have x≥0 and y≥0 ⇒ ((√x) +(√y))^2 =x+y ⇒x+y +2(√(xy))=x+y ⇒ xy=0 ⇒x=0 or y=0 x=0 ⇒y^2 =1 ⇒y=1 y=0⇒x^2 =1⇒x=0 so the solution are (1,0)and (0,1)

fromtheequalitywehavex⩾0andy⩾0⇒(x+y)2=x+y⇒x+y+2xy=x+y⇒xy=0⇒x=0ory=0x=0⇒y2=1⇒y=1y=0⇒x2=1⇒x=0sothesolutionare(1,0)and(0,1)

Commented by behi83417@gmail.com last updated on 28/Jul/18

thank you both sirs:MrW3 & mr abdo.

thankyoubothsirs:MrW3&mrabdo.

Terms of Service

Privacy Policy

Contact: info@tinkutara.com