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Question Number 40917 by Tawa1 last updated on 29/Jul/18

	Answered by tanmay.chaudhury50@gmail.com last updated on 30/Jul/18

	$3 - 1 \times i_{3} + 1 \times i_{2} - 4 \times i_{3} - 15 = 0$ $i_{2} - 5 i_{3} = 12 . . . e q n 1$ $3 - 2 i_{2} + 2 i_{1} - 2 i_{2} + 3 - 1 \times i_{2} + 1 \times i_{3} - 3 = 0$ $2 i_{1} - 5 i_{2} + i_{3} = - 3 . . . e q n 2$ $10 - 3 i_{1} - 2 i_{1} + 2 i_{2} - 3 = 0$ $- 5 i_{1} + 2 i_{2} + 7 = 0$ $5 i_{1} - 2 i_{2} = 7 . . . e q n 3$ $f r o m e q n 1 i_{3} = \frac{i_{2} - 12}{5}$ $f r l m e q n 3 i_{1} = \frac{7 + 2 i_{2}}{5}$ $p u t i n e q n 2$ $2 i_{1} - 5 i_{2} + i_{3} = - 3$ $2 (\frac{7 + 2 i_{2}}{5}) - 5 i_{2} + \frac{i_{2} - 12}{5} = - 3$ $14 + 4 i_{2} - 25 i_{2} + i_{2} - 12 = - 15$ $- 20 i_{2} = - 15 - 14 + 12$ $- 20 i_{2} = - 17$ $i_{2} = \frac{17}{20} = \frac{85}{100}$ $i_{1} = \frac{7 + 2 i_{2}}{5} = \frac{7 + \frac{34}{20}}{5} = \frac{174}{200} = \frac{87}{100}$ $i_{3} = \frac{i_{2} - 12}{5} = \frac{\frac{17}{20} - 12}{5} = \frac{17 - 240}{100} = \frac{- 223}{100}$ $i_{1} = \frac{85}{100} i_{2} = \frac{87}{100} i_{3} = \frac{- 223}{109}$ $i_{3} = - v e t h a t m e a n s t r u e d i t e c t i o n o f i_{3} i s o p p o s i t e t 0 t h e t r u e d i r e c t i o n . . .$
	Commented by Tawa1 last updated on 30/Jul/18

	$God bless you sir .$
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