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Question Number 40965 by Glorious Man last updated on 30/Jul/18

Answered by tanmay.chaudhury50@gmail.com last updated on 30/Jul/18

t=x^5 −x^3 dt=5x^4 −3x^2 dx =−2∫((5x^4 −3x^2 dx)/(x^5 −x^3 )) =−2∫((d(x^5 −x^3 ))/(x^5 −x^3 )) =−2ln(x^5 −x^3 )+c

t=x5−x3dt=5x4−3x2dx=−2∫5x4−3x2dxx5−x3=−2∫d(x5−x3)x5−x3=−2ln(x5−x3)+c

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