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Question Number 41086 by byaw last updated on 01/Aug/18

$$\mathrm{A}\mathrm{woman}\mathrm{is}\mathrm{four}\mathrm{times}\mathrm{older}\mathrm{than}$$$$\mathrm{her}\mathrm{daughter}.\mathrm{Six}\mathrm{years}\mathrm{ago}\mathrm{the}$$$$\mathrm{product}\mathrm{of}\mathrm{their}\mathrm{ages}\mathrm{is}136.$$$$\mathrm{How}\mathrm{old}\mathrm{is}\mathrm{the}\mathrm{woman}?$$

Answered by tanmay.chaudhury50@gmail.com last updated on 01/Aug/18

$$woman=4xdaughtet=x$$$$(4x-6)(x-6)=136$$$$4x^2-24x-6x+36-136=0$$$$4x^2-30x-100=0$$$$4x^2-40x+10x-100=0$$$$4x(x-10)+10(x-10)=0$$$$(x-10)(4x+10)=0$$$$x=10daughterage$$$$womanave=40$$

Commented by byaw last updated on 02/Aug/18

$$thankyouverymuch.$$

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