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Question Number 41095 by Necxx last updated on 02/Aug/18
Forallrealvaluesofxsolvetheinequality∣1−x3x6−2x3+5∣⩽14
Answered by ajfour last updated on 02/Aug/18
letx3−1=t⇒∣tt2+4∣⩽14or−14⩽tt2+4⩽14ort2+4t+4⩾0andt2−4t+4⩾0⇒t∈(−∞,∞)thesameforx.
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