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Question Number 41710 by Tawa1 last updated on 11/Aug/18

Factorize:  60x^3 y + 115x^2 y^2  − 120xy^3

Factorize:60x3y+115x2y2120xy3

Answered by alex041103 last updated on 11/Aug/18

60x^3 y + 115x^2 y^2  − 120xy^3 =  =5xy(12x^2 +23xy−24y^2 )  Then let′sfind x_(1,2) for  (12)x^2 +(23y)x+(−24y^2 )=0  ⇒x_(1,2) =((−23y±(√(529y^2 +1152y^2 )))/(24))=  =((±(√(1681))−23)/(24))y=((−23±41)/(24))y=−(8/3)y or (3/4)y  ⇒(12x^2 +23xy−24y^2 )=12(x+(8/3)y)(x−(3/4)y)  =(3x+8y)(4x−3y)  ⇒60x^3 y + 115x^2 y^2  − 120xy^3 =  =5xy(3x+8y)(4x−3y)

60x3y+115x2y2120xy3==5xy(12x2+23xy24y2)Thenletsfindx1,2for(12)x2+(23y)x+(24y2)=0x1,2=23y±529y2+1152y224==±16812324y=23±4124y=83yor34y(12x2+23xy24y2)=12(x+83y)(x34y)=(3x+8y)(4x3y)60x3y+115x2y2120xy3==5xy(3x+8y)(4x3y)

Commented by Tawa1 last updated on 11/Aug/18

I really appreciate sir. God bless you sir

Ireallyappreciatesir.Godblessyousir

Answered by ajfour last updated on 11/Aug/18

=5xy(12x^2 +23xy−24y^2 )  =5xy(12x^2 +32xy−9xy−24y^2 )  =5xy[4x(3x+8y)−3y(3x+8y)]  =5xy(3x+8y)(4x−3y) .

=5xy(12x2+23xy24y2)=5xy(12x2+32xy9xy24y2)=5xy[4x(3x+8y)3y(3x+8y)]=5xy(3x+8y)(4x3y).

Commented by Tawa1 last updated on 11/Aug/18

God bless you sir

Godblessyousir

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