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Question Number 41902 by upadhyayrakhi20@gmail.com last updated on 15/Aug/18
tan3θtan2θ=1findthegeneralsolution......
Answered by MJS last updated on 15/Aug/18
tan3θtan2θ−1=0−2cos5θcos5θ+cosθ=0(sorrynotimefortypingatthemoment)cos5θ=0∧cos5θ+cosθ≠0θ=±π10+πz∨θ=±3π10+πz;z∈Z
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