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Question Number 42007 by jasno91 last updated on 16/Aug/18

Answered by MJS last updated on 16/Aug/18

$$\mathrm{lcm}(3x,4x)=12x=180$$$$x=\frac{180}{12}=15$$$$3x=45=3^2{5}^1$$$$4x=60=2^2{3}^1{5}^1$$$$\mathrm{lcm}(3^2{5}^1,2^2{3}^1{5}^1)=2^2{3}^{2}5=180$$

Answered by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18

$$twonumberare3xand4x$$$$lcm=x\times 3\times 4=12x$$$$12x=180$$$$x=\frac{180}{12}=15$$$$sooneis3\times 15=45$$$$anotheris4\times 15=60$$

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