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Question Number 42110 by rahul 19 last updated on 18/Aug/18

Commented by Tawa1 last updated on 19/Aug/18

sweet

$$\mathrm{sweet} \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 18/Aug/18

first variety say A in basket (A+A+A+A)  second variety say B in basket(B+B+B+B)    third variety say C in baskeg(C+C+C+C)  distribution for first person is  4c_2 ×4c_2 ×4c_2 =6×6×6=216  distributiin for second person=2c_2 ×2c_2 ×2c_2 =1  total 216+1=217    pls check

$${first}\:{variety}\:{say}\:{A}\:{in}\:{basket}\:\left({A}+{A}+{A}+{A}\right) \\ $$$${second}\:{variety}\:{say}\:{B}\:{in}\:{basket}\left({B}+{B}+{B}+{B}\right) \\ $$$$ \\ $$$${third}\:{variety}\:{say}\:{C}\:{in}\:{baskeg}\left({C}+{C}+{C}+{C}\right) \\ $$$${distribution}\:{for}\:{first}\:{person}\:{is} \\ $$$$\mathrm{4}{c}_{\mathrm{2}} ×\mathrm{4}{c}_{\mathrm{2}} ×\mathrm{4}{c}_{\mathrm{2}} =\mathrm{6}×\mathrm{6}×\mathrm{6}=\mathrm{216} \\ $$$${distributiin}\:{for}\:{second}\:{person}=\mathrm{2}{c}_{\mathrm{2}} ×\mathrm{2}{c}_{\mathrm{2}} ×\mathrm{2}{c}_{\mathrm{2}} =\mathrm{1} \\ $$$${total}\:\mathrm{216}+\mathrm{1}=\mathrm{217}\:\:\:\:{pls}\:{check} \\ $$

Commented by rahul 19 last updated on 18/Aug/18

Ans is 19.

$$\mathrm{Ans}\:\mathrm{is}\:\mathrm{19}. \\ $$

Commented by tanmay.chaudhury50@gmail.com last updated on 18/Aug/18

give me time...

$${give}\:{me}\:{time}... \\ $$

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