Calculate the density of 1 mole of oxygen at a pressure of 4×10^4 Nm^(−2) and temperature of 273.2K.


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Question Number 42128 by Necxx last updated on 18/Aug/18

$C a l c u l a t e t h e d e n s i t y o f 1 m o l e o f$ $o x y g e n a t a p r e s s u r e o f 4 \times 10^{4} {N m}^{- 2}$ $a n d t e m p e r a t u r e o f 273.2 K .$
Commented by Necxx last updated on 18/Aug/18

$p l e a s e c h e c k t h i s a p p r o a c h$ $n = 1 P = 4 \times 10^{4} N / m^{2} T = 273.2 K$ $R = 8.31 {J m o l}^{- 1} K^{- 1}$ $m o l a r m a s s o f o x y g e n = 32 \times 10^{- 3} k g / m o l$ $m a s s o f 1 m o l e = 3.5 \times 10^{- 26}$ $∴ V = \frac{n R T}{P} = \frac{1 \times 8.31 \times 273.2}{4 \times 10^{4}} = 5.67 \times 10^{- 2} l$ $s i n c e d e n s i t y = ρ = m / V t h e n$ $= \frac{3.5 \times 10^{- 26}}{5.67 \times 10^{- 2}} = 0.617 \times 10^{- 24} k g / l$ $p l s c h e c k a n d c o m m e n t$
Commented by Necxx last updated on 18/Aug/18

$p l e a s e h e l p i t s u r g e n t$
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