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Question Number 42175 by lucha116 last updated on 19/Aug/18

sin3x+sin5x=2(cos^2 2x−sin^2 3x)

$${sin}\mathrm{3}{x}+{sin}\mathrm{5}{x}=\mathrm{2}\left({cos}^{\mathrm{2}} \mathrm{2}{x}−{sin}^{\mathrm{2}} \mathrm{3}{x}\right) \\ $$

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