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Question Number 42352 by Raj Singh last updated on 24/Aug/18
Answered by tanmay.chaudhury50@gmail.com last updated on 24/Aug/18
∠AOC=∠BOD=2x(verticallyoppositeanglevoa)∠AOB=∠COD=2y(voa)2x+2y+2x+2y=360ox+y+x+y=180ox=12∠AOCx=12∠BOD2y=∠AOBsox+2y+x=180o12∠AOC+∠AOB+12∠BOD=180o∠POA+∠AOB+∠BOQ=180osoOPandOQonthesameline...since∠POQis=180o
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