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Question Number 42357 by preet last updated on 24/Aug/18

Answered by tanmay.chaudhury50@gmail.com last updated on 24/Aug/18

$$\overrightarrow{v}=\frac{d\overrightarrow{r}}{dt}=\frac{d}{dt}(3ti-t^{2}j+4k)$$$$\overrightarrow{v}=3i-2tj+0.k$$$${\left(\overrightarrow{v}\right)}_{t=5sec}=3i-10j+0.k$$$$so\mid {\left(\overrightarrow{v}\right)}_{t=5sec}\mid =\sqrt{3^2+{(-10)}^2+0^2}=\sqrt{109}meter/sec$$

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