cosec2A+cosec4A+cosec8A=cotA−cot8A(prlve ghis)


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Question Number 42519 by gyugfeet last updated on 27/Aug/18

$c o s e c 2 A + c o s e c 4 A + c o s e c 8 A = c o t A - c o t 8 A (p r l v e g h i s)$
	Answered by tanmay.chaudhury50@gmail.com last updated on 27/Aug/18

	$c o t A - (c o s e c 2 A + c o s e c 4 A + c o s e c 8 A)$ $c o t A - c o s e 2 A - (c o s e c 4 A + c o s e c 8 A)$ $\frac{c o s A}{s i n A} - \frac{1}{2 s i n A c o s A} - (c o s e c 4 A + c o s e c 8 A)$ $\frac{2 {c o s}^{2} A - 1}{2 s i n A c o s A} - (c o s e c 4 A + c o s e c 8 A)$ $\frac{c o s 2 A}{s i n 2 A} - c o s e c 4 A - c o s e c 8 A$ $c o t 2 A - c o s e c 4 A - c o s e c 8 A$ $\frac{c o s 2 A}{s i n 2 A} - \frac{1}{s i n 4 A} - c o s e c 8 A$ $\frac{2 {c o s}^{2} 2 A - 1}{2 s i n 2 A c o s 2 A} - c o s e c 8 A$ $\frac{c o s 4 A}{s i n 4 A} - \frac{1}{s i n 8 A}$ $\frac{2 {c o s}^{2} 4 A - 1}{s i n 8 A}$ $\frac{c o s 8 A}{s i n 8 A}$ $c o t 8 A p r o v e d$
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